Resolve using the Graphical Method the following problem:
| Maximize | Z = f(x,y) = 3x + 2y |
| subject to: | 2x + y ≤ 18 |
| 2x + 3y ≤ 42 | |
| 3x + y ≤ 24 | |
| x ≥ 0 , y ≥ 0 |

| Extreme point | Coordinates (x,y) | Objective value(Z) |
| O | (0,0) | 0 |
| C | (0,14) | 28 |
| G | (3,12) | 33 |
| H | (6,6) | 30 |
| F | (8,0) | 24 |
COMPARING: GRAPHICAL METHOD VS. SIMPLEX METHOD
The successive boards that we have built during the simplex method, provide us the value of the objective function at different vértices, fitting up, at the same time, the coefficients of initial and slack variables.
In the first iteration (Board I) have remained all the equal coefficients, has been calculated the objective function value at the vertex (0,0) that is the value which belong to the basic variables, been 0 the result.
| Board I . 1st iteration | |||||||
| 3 | 2 | 0 | 0 | 0 | |||
| Base | Cb | P0 | P1 | P2 | P3 | P4 | P5 |
| P3 | 0 | 18 | 2 | 1 | 1 | 0 | 0 |
| P4 | 0 | 42 | 2 | 3 | 0 | 1 | 0 |
| P5 | 0 | 24 | 3 | 1 | 0 | 0 | 1 |
| Z | 0 | -3 | -2 | 0 | 0 | 0 | |

Now, it moves through the edge (0,0) F, estimating the value of the Z function, until get to F. This step is translated like the second repetition in the Simplex Method, contributing the II Board, in which have been calculated the value corresponds to the vertex F(8,0): Z=f(8,0)=24.
| Board II . 2nd iteration | |||||||
| 3 | 2 | 0 | 0 | 0 | |||
| Base | Cb | P0 | P1 | P2 | P3 | P4 | P5 |
| P3 | 0 | 2 | 0 | 1/3 | 1 | 0 | -2/3 |
| P4 | 0 | 26 | 0 | 7/3 | 0 | 1 | -2/3 |
| P1 | 3 | 8 | 1 | 1/3 | 0 | 0 | 1/3 |
| Z | 24 | 0 | -1 | 0 | 0 | 1 | |

Keeps on for the FH edge, until arrive to H, where it stops and diplays the data from III Board. At this third iteration has been calculated the value that corresponds to the vertex H(6,6): Z=f(6,6)=30.
| Board III . 3rd iteration | |||||||
| 3 | 2 | 0 | 0 | 0 | |||
| Base | Cb | P0 | P1 | P2 | P3 | P4 | P5 |
| P2 | 2 | 6 | 0 | 1 | 3 | 0 | -2 |
| P4 | 0 | 12 | 0 | 0 | -7 | 1 | 4 |
| P1 | 3 | 6 | 1 | 0 | -1 | 0 | 1 |
| Z | 30 | 0 | 0 | 3 | 0 | -1 | |

We keep on doing calculations trough the HG edge, until the G vertex. The data that is reflected belong to IV Board, concluding with the same and warning that it has ended up (checking before that the solution does not get better when it moves around the GC edge).
| Board IV . 4th iteration | |||||||
| 3 | 2 | 0 | 0 | 0 | |||
| Base | Cb | P0 | P1 | P2 | P3 | P4 | P5 |
| P2 | 2 | 12 | 0 | 1 | -1/2 | 0 | 0 |
| P5 | 0 | 3 | 0 | 0 | -7/4 | 0 | 1 |
| P1 | 3 | 3 | 1 | 0 | -3/4 | 0 | 0 |
| Z | 33 | 0 | 0 | 5/4 | 0 | 0 | |

The maximum value for the objective function is 33, and corresponds to x = 3 and y = 12 (vertex G). Besides, it can be checked than the value of the function at vertex C (0,14), doesn’t surpass 33.